ASAS 1ICCT Kanaya Soal no1:R4+R5= 1/10 + 1/10 = 2/10 = 10/2 = 5R2+R45+R6= 5+10+10 = 25Rs= 25+10= 35Rp= 35×10 : 35+10 = 7,78Rtotal= 7,78+10 = 17,78I= V/R = 10,7/17,78 = 0,602ANALISIS phEtR= 17,78I= 0,602 R45= 5Rs= R45+3+R6+R7+R8 = 5+10+10+10 = 35Rp= 35×10 : 35+10 = 7,78Rtotal= 7,78+10+10 = 27,78I= 0,360Analisis phEtRtotal= 27,78I= 0,360 R3 + R4 = 3.8 + 10 = 13.8 ohmR2 paralel R34 = (10 x 13.8) / (10 + 13.8) = 138 / 23.8 = 5.8 ohmR5 paralel R6 = (10 x 10) / (10 + 10) = 100 / 20 = 5 ohmR top = 5 + 5 = 10 ohmR98 = 10 + 5 = 15 ohmR right = (10 x 15) / (10 + 15) = 150 / 25 = 6 ohmR total = 10 + 5.8 + 6 = 21.8 ohm I= 14/21.8 = 0,642Analisis PhEtRtotal= 21.8 oh,I= 0,642 R total:Rtotal = 5.37 + 10 = 15.37 Arus total:I = 11.6 / 15.37 = 0.75 AR total = 15.37 I total = 0.75 AAnalisis phEt:I= 0.75