Rangkaian Seri, paralel & campuran

  • Seri → ditambah

    Rseri=R3+R4

  • Paralel → dibalik lalu dijumlah

    1Rtotal=1R1+1R2+

    1Rs 


SAS ICCT_Andro_2025

Mr. Bayu : Bagus sudah menyelesaikan semua soal dan bonus
👍

Soal 1

Cari R total 

Rp1 = 1/10 +1/10 = 2/10 = 10/2 =5Ω

Rs1=10+5+10+10=35Ω

Rp2=1/10+1/35 =7+2/70=11/90=90/11=7,77Ω

Rs2=10+7,77=17,77Ω

 

Cari I / Arus

V/R = 10/17,77 = 0,60A



Soal 2

Cari R total

Rp1 = 1/10 +1/10 =2/10 =10/2 =5Ω

Rs1 = 10+5+10+10+10= 45Ω

Rp2 = 1/10 +1/45 = 9+2/90 =11/90 =90/11 = 8,18Ω

Rs2 = 10+8,18= 18,18Ω

Cari I/ arus

V/R = 10/ 18,18 = 0,55A



Soal 3

Cari R total

Rp1 = 1/10 +1/10 =2/10 =10/2 =5Ω

Rs1 = 10+5+5+5+10=45Ω

Rs2 = 10+3,8=13,8Ω

Rp2 = 1/13,8 + 1/35= 175+69/2415 = 244/ 2415= 2415/244= 9,89Ω

Rs3 = 10+9,89 = 19,89Ω

 

Cari I/ arus

V/R = 14/19,89=0,70A



Soal 4

Cari R total

Rp1 = 1/10 +1/10 =2/10 =10/2 =5Ω

Rs1 = 10+5+5+5+10=45Ω

Rs2 = 10+3,8=13,8Ω

Rp2 = 1/13,8 + 1/35= 175+69/2415 = 244/ 2415= 2415/244= 9,89Ω

Rs3 = 10+9,89 = 19,89Ω

Cari I/ arus

V/R = 23,4/19,89=1,17A

koreksi lagi andro (Mr Bayu)

Soal 5

Cari R total

Rp1 = 1/10 +1/10 =2/10 =10/2 =5Ω

Rs1 = 10+5+5+5+10=45Ω

Rs2 = 10+3,8=13,8Ω

Rp2 = 1/13,8 + 1/35= 175+69/2415 = 244/ 2415= 2415/244= 9,89Ω

Rs3 = 10+9,89 = 19,89Ω

 

Cari I/ arus

V/R = 11,6/19,89=0,5A